Question

19. Find the area of a sector of a circle with radius 6 cm if the angle
of the sector is 60°




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Answer 1

Answer:

Area of sector = 18.85 cm^2

Step-by-step explanation:

Area of sector = titha/360 × pi ×r^2

= 60/360 × 22/7 × 6 × 6

= 132/7

= 18.85 cm^2

Answer 2

$\huge {\red{\boxed{ \overline{ \underline{ \mid\mathfrak{An}{\mathrm{sw}{ \sf{er}} \colon\mid}}}}}}$

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➠ Given :

Radius (r) = 6 cm

Angle of the sector (θ) = 60°

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➠ To Find :

We have to find the area of the sector of the circle.

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➠ Solution :

We know the formula to find the Area of the sector of the circle.

$\Large{\star{\boxed{\sf{Area = \frac{θ}{360^{\circ}} \pi r^2}}}}$

(Putting Values)

$\sf{Area = \frac{\cancel{60}}{\cancel{360}} \times \frac{22}{7} \times 6 \times 6} \\ \\ \sf{\implies Area = \frac{1}{\cancel{6}} \times \frac{22}{7} \times 6 \times \cancel{6}} \\ \\ \sf{\implies Area = \frac{22}{7} \times 6} \\ \\ \sf{\implies Area = \frac{132}{7}} \\ \\ \sf{\implies Area = 18.85 \: cm^2}$

$\Large{\mapsto{\boxed{\sf{Area = 18.85 \: cm^2}}}}$