Question

19.
Find the quadratic polynomial whose zeroes are
$2 \sqrt{7 \: \: } and \: - 5 \sqrt{7}$
​

Answer 1

HOL@ M@T€...!!!

________☺️________

Zeroes :- 2√7 and -5√7

To find :- quadratic polynomial

Using the formula:-

x²-(sum of zeroes)x+(product of zeroes)

•Sum of zeroes = 2√7 +(-5√7)

=2√7-5√7

=-3√7

Product of zeroes = 2√7 × (-5√7)

=-10×7

=-70

Quadratic polynomial=p(x)

p(x) = x²-(sum)x+product

p(x) = x²-(-3√7)x+(-70)

p(x) = x²+3√7x-70

$<marquee>$#BeBrainly✔️❤️✌️

Answer 2

Hello.

Here is your answer below,

Given values are

x = (2/√7, -5√7)

So now going to solution

$x = ( \frac{2}{ \sqrt{7} } \: and \: \frac{5}{ \sqrt{7} } ) \\ = >( x - \frac{2}{ \sqrt{7} } )(x + \frac{5}{ \sqrt{7} } ) = 0 \\ = > x {}^{2} + \frac{5}{ \sqrt{7} } x - \frac{2}{ \sqrt{7} } x - \frac{10}{7} = 0 \\ = > 7\sqrt{7} x {}^{2} + 35x - 14x - 10 \sqrt{7} = 0 \\ = > 7 \sqrt{7} x {}^{2} + 21x - 10 \sqrt{7}$

I hope that helps you