Math, asked by Vikasnayak123, 9 months ago

19. find the roots of the equation
6x*+7x-10-0
By factorisation method
6x² + 7x - 100
6x + 12x - 5x - 10 = 0)
6x(x+2) - 5 (x+2) = 0),
(x+2) (6x - 5)=0)
x+ 2 = 0 OR 6x - 5=0. in second step how 12 came

Answers

Answered by adinarayanakanta
3

Answer:

7x =12x-5x

Step-by-step explanation:

6x^2×10=60x^2=12x×5x

so mark it as brainliest question

Answered by hemant9999
3

Step-by-step explanation:

for factorization method we have to split the middle term of x such that its addition is equal to middle term and multiplication is equal to the product of constant and the coefficient of x^2

The equation is 6x^2+7x-10=0

it is on the form of Ax^2+By+c=0

A×C=-60

split this in two numbers such that

its multiplication is -60x and addition is +7x

so the two numbers are

12x and -5x

solve further for answer

PLEASE MARK BRAINLIEST

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