Question

19. Five years ago, a man was five times as old as his son. Eight years hence, the
man's age will be two years less than three times his son age. Find their present
ages. eska answer he 17 yr 65 yr . aaplog process bata dijiye.​

Answer 1

Answer:

ANSWER

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years