Math, asked by saikumari1977, 4 months ago

19)
From the given figure, PAQ is a tangent of a circle, PBD is a straight line and
<APB = 52º and <ACB = 48º. Find the angles.

(i)
BAP =
A) 48°
B) 52°
C) 100°
D) 60°
ZABD =
A) 480
B) 52°
C) 100°
D) 80°
( )
(iii) ZQAD =
A) 120°
B) 58°
C) 100°
D) 48°
(iv)
BCD
A) 1540
B) 54°
C) 78°
D) 148°
( )
(v)
ZADB =
A) 480
B) 549
C) 52°
D) 60°​

Answers

Answered by Anonymous
7

Answer:

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1
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