Math, asked by venukoushik, 4 months ago

19. From the sum of 2b2 + 3bc-b2-bc-c? and bc + 2c2. Subtract the
sum of 3b2 - c? and 4a²b-8ab2.​

Answers

Answered by sipra7755
5

Answer:

-2b²+3bc+c²+c-4a²b+8ab

Step-by-step explanation:

sum:2b²+3bc-b²-bc-c and bc +2c²

=(2b²-b²)+(3bc+bc-bc)+2c²-c

=b²+3bc-c²+2c²

sum:3b²-c and 4a²b-8ab²

=3b²-c+4a²b-8ab²

subtraction:=b²+3bc-c²+2c²-(3b²-c+4a²b-8ab)

=b²+3bc-c²+2c²-3b²+c-4a²b+8ab

=(b²-3b²)+3bc-(c²+2c²)+c-4a²b+8ab

=-2b²+3bc+c²+c-4a²b+8ab

hope it helped u buddy

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