Question

19 g of water at 30°C and 5 g of ice at -20°C are
mixed together in a calorimeter. What is the final
temperature of the mixture? Given specific heat of
ice = 0.5 cal g? °C and latent heat of fusion of
ice = 80 cal g'.
(a) 0°C (b) -5°C (c) 5°C (d) 10°C
​

Answer 1

Answer:

30g of ice at -15 degree celcius is added to 100g of water at 25 degree celcius. What is the final temperature? T1=ice T2=H2O at equilibrium must have m1c1(Te-T1)+m1k=m2c2(T2-Te) [k=3.3x10^5 J/K fusion heat coeff.] then Te=(m1c1T1+m2c2T2-m1k)/(m1c1+m2c2) T1=268 k T2=298 K c1=2090 J/(kg K) c2=4186 J/(kg K) Te=(0.02*2090*268+0.1*4186*298-0.02*3.3… / (0.02*2090+0.1*4186) Te=280,9 K Te=7.8 C Final Temperature is 7.8 C

Source https://www.physicsforums.com/threads/what-is-the-final-temperature.701958/