Question

19 gram mixture of Na2CO3 and NaHCO3 on heating gives 2.2 gram CO2 gas. find % NaHCO3 (By mass) in mixture.

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Answer 1

Answer:

solve the numbers below and u will find d the answers

Answer 2

Answer:

44.21% of NaHCO3

Step-by-step explanation:

So NaHCO3 can produce CO2 on heating as per the following equation:

2NaHCO3 ----> Na2CO3 + H2O + CO2

Now,

2 moles of NaHCO3 produces 1 mole of CO2

We have 2.2 grams of CO2 which is 0.05 moles of CO2

Therefore 0.1 mole of NaHCO3 produces 0.05 moles of CO2

The molar mass of NaHCO3 => 23 + 1 + 12 + 3(16) = 84 gm

Hence, 0.1 mole of NaHCO3 = 8.4 gram

Therefore percentage of NaHCO3 in 19 gm mixture

= (8.4/19) * 100

≈ 44.21%