19. How many different 6 digit numbers can be formed from the digits 4, 2, 5, 0, 6 and 7,
no digit being repeated ? How many of these will have 0 in the ten's place.
with the help of (permutations and combinations)
please answer it's urgent
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Answer:
no. of 6 digit numbers will be = 6! = 6×5×4×3×2×1
In 5! or 5×4×3×2×1 numbers, the '0' will be in ten's place
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