19. If p(k)= k2 – 2k – 3, find the values of p(0),p(-1).
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see the above pic for answer
I hope you get your answer
thanks for asking
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Step-by-step explanation:
p(0) =0×2-0×2-3
= -3
p(-1) =-1×2-(-1) ×2-3
=-2+2-3
=-3
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