Question

19) If pth qth and rth terms of a gp are X, Y, Z find value of

x(q-r) ×y(r-p) × z( p-q)
the bracket things are in power to the x y z respect ively​

Answer 1

do not understand the question

Answer 2

Answer:

HEY MATE HERE IS YOUR ANSWER...

Given,

Given,arp−1=x

Given,arp−1=xarq−1=y

Given,arp−1=xarq−1=yarr−1=z

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r⇒(arq−1)r−p=yr−p

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r⇒(arq−1)r−p=yr−p⇒(arr−1)p−q=zp−q

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r⇒(arq−1)r−p=yr−p⇒(arr−1)p−q=zp−qxq−ryr−pzp−q=(arp−1)q−r(arq−1)r−p(arr−1)p−q

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r⇒(arq−1)r−p=yr−p⇒(arr−1)p−q=zp−qxq−ryr−pzp−q=(arp−1)q−r(arq−1)r−p(arr−1)p−qxq−rxyr−pxzp−q=a(p+q+r−p−q−r)r(pq+qr+rp+p+q+r−qp−rq−pr−p−q−r)

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r⇒(arq−1)r−p=yr−p⇒(arr−1)p−q=zp−qxq−ryr−pzp−q=(arp−1)q−r(arq−1)r−p(arr−1)p−qxq−rxyr−pxzp−q=a(p+q+r−p−q−r)r(pq+qr+rp+p+q+r−qp−rq−pr−p−q−r)⇒xq−rxyr−pxzp−q=a0r0

Given,arp−1=xarq−1=yarr−1=z⇒(arp−1)q−r=xq−r⇒(arq−1)r−p=yr−p⇒(arr−1)p−q=zp−qxq−ryr−pzp−q=(arp−1)q−r(arq−1)r−p(arr−1)p−qxq−rxyr−pxzp−q=a(p+q+r−p−q−r)r(pq+qr+rp+p+q+r−qp−rq−pr−p−q−r)⇒xq−rxyr−pxzp−q=a0r0∴xq−rxyr−pxzp−q= 1.

HOPE THIS HELPS U....PLEASE MARK

ME AS BRAINIEST ....AND GIVE ME A

THANKS......PLEASE....