Question

19. If (tan 0 + cot O) = 5, find the value of (tan2 O + cot2 O).​

Answer 1

Answer:

tan 0+ cot0 = 5

squaring both sides

(tan0+ cot0)² = 5²

tan²0 + cot²0 + 2 tan0*cot 0= 25

tan²0+cot²0 + 2tan0 *1/tan0 =25

tan²0+ cot²0 +2 = 25

tan²0 + cot²0 = 25-2

tan²0+ cot²0 = 23

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Answer 2

Step-by-step explanation:

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