Question

19. If the base of 5² is increased by 20% then how much percent will increas
the value ?​

Answer 1

Base = 5

Power = 2

if base is increased by 20%, then

Base = 5+5×20%

= 5+1

= 6

if base = 5

then, 5²= 25

if base = 6

then, 6²= 36

Difference in values = 36-25 = 11

increase in percentage = 11/25×100 =44%

Answer 2

Answer:

Required percentage increase 44%

Step-by-step explanation:

Given number is ${5}^{2}$ and base of ${5}^{2}$ is increased by 20%.

Here we want to find how much percent will increase the value ?

Here base of 5² is 5 and power is 2.

We know,

x% increase of y $= \frac{100 + x}{100} \times y$

So,20% increase of 5

$= \frac{100 + 20}{100} \times 5 \\ = \frac{120}{100} \times 5 \\ = 6$

Now 5² becomes 6².

Value of 5²$= 25$

and value of 6² $= 36$

Value increases $= (36 - 25) = 11$

Here 25 means 100%

So, 1 means $\frac{100}{25} \%$

and 11 means

$\frac{100}{25} \times 11 \\ = 4 \times 11 \\ = 44\%$

This is a problem of Power of indices.

Some important formulas of Power of indices:

${x}^{0} = 1 \\ {x}^{1} = x \\ {x}^{a} \times {x}^{b} = {x}^{a + b} \\ \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} \\ {x}^{ {y}^{a} } = {x}^{ya} \\ {x}^{ - 1} = \frac{1}{x} \\ {x}^{a} \times {y}^{a} = {(xy)}^{a}$

Know more about Power of indices,

1.https://brainly.in/question/21620304

2.https://brainly.in/question/10752814

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