Question

19 If the distance between (P, -5) and (2, 7) is 13 units, then find the value of 'P'.

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Answer 1

Answer:

distance = root of ( x2-x1)² + (y2-y1)²

13 = root of (2-p)² + (7+5)²

169 = 4-4p+p² + 144

169 = p²-4p+148

p²-4p-21=0

(p-7) (p+3) =0

p = 7 or -3

Answer 2

Answer:

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