Math, asked by subhashchandra3719, 1 day ago

19- If the points A(-2,1), B( a , b) and C( 4,-1) are collinear and a-b= 1. then the value of a and bis (a) a =0,b=1 (b) a =1, b = 0 (c) a = 0,b=0 (d) a =2, b = 1​

Answers

Answered by MissRudeGirl
3

The given points are A (−2, 1), B (a, b) and C (4, −1). Since the given points are collinear, the area of the triangle ABC is 0. Thus, the values of a and b are 1 and 0, respectively

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Answered by sofianhendrik
0

Answer:

The given points are A (−2, 1), B (a, b) and C (4, −1). Since the given points are collinear, the area of the triangle ABC is 0. Thus, the values of a and b are 1 and 0, respectively

Step-by-step explanation:

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