Question

19.If y = 3 sinx + 4 cosx , then dy 2 y2 + (ay)? dx​

Answer 1

Step-by-step explanation:

3

dx

d

(sin(xy))+4

dx

d

(cos(xy))=

dx

d

(5)

⇒3cos(xy)

dx

d

(xy)−4sin(xy)

dx

d

(xy)=0

⇒(3cos(xy)−4sin(xy))

dx

d

(xy)=0

⇒(3cos(xy)−4sin(xy))(x

dx

dy

+y)=0

⇒3cos(xy)−4sin(xy)=0 and x

dx

dy

+y=0

⇒3cos(xy)=4sin(xy) and x

dx

dy

=−y

⇒tanxy=

4

3

and

dx

dy

=

x

−y

∴

dx

dy

=

x

−y