Question

19. In a college, 240 students play cricket, 180 students
play football, 164 students play hockey, 42 play
both cricket and football, 38 play both football and
hockey, 40 play both cricket and hockey and 16 play
all the three games. If each student participate in
atleast one game, then find (i) the number of
students in the college (ii) the number of students
who play only one game.​

Answer 1

Answer:

1: the total number of students is 620. 2: the number of students who play only one game is 420

Answer 2

Answer:

5

Step-by-step explanation:

A – by bus  B – by bicycle  C – on foot  n(A) = 25  n(B) = 20  n(C) = 30  n(A ∩ B ∩ C ) = 10  n(A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n(A ∩ B) – n(B ∩ C) – n(C ∩ A) + n(A ∩ B ∩ C)  50 = 25 + 20 + 30 – (10 + x) – (10 + y) – (10 + z) + 10  50 = 75 – 10 – x – 10 – y – 10 – z + 10  = 75 – 20 – (x + y + z) = 55 – (x + y + z)  x + y + z = 55 – 50 = 5  ∴ The number of students who come to school exactly by two modes of transport