Physics, asked by adityarai3692, 5 hours ago

19. In an AC circuit with all components connected in
series, the emf and the current are given by
TC
V=200 sin 314t +
volt and I=5 sin 314t ampere.
6

27.
Obtain (1) the peak values of emf and current, (i) the
frequency of the AC source, (iii) the phase difference
between V and I (iv) impedance of the circuit

Answers

Answered by harshumtayade
0

Answer:

19. In an AC circuit with all components connected in

series, the emf and the current are given by

TC

V=200 sin 314t +

volt and I=5 sin 314t ampere.

6

27.

Obtain (1) the peak values of emf and current, (i) the

frequency of the AC source, (iii) the phase difference

between V and I (iv) impedance of the circuit

Explanation:

don't no

Answered by hotelcalifornia
1

Given:

V=200sin(314t)V

I=5 sin(314t)A

To find:

  1. Peak value of EMF and current.
  2. Frequency of the AC source.
  3. Phase difference between V and I.
  4. Impedance of the circuit.

Solution:

Step 1

Standard form of equation is A=A_{o}sinωt ; where A_{o} is the peak value.

We have been given the equations for a variable EMF and current with respect to time t.

Hence,

Peak value of EMF = 200V

Peak value of Current = 5A

Step 2

If we consider the standard form of an equation for current,

I=I_{o}sint)

Comparing it with the given equation,

We get  ωt =314t

We know,  ω = 2πf ; where f is the frequency

Hence,

2πf =314

2(3.14)f=314

f=50Hz

Hence, frequency is 50Hz.

Step 3

We know, if in a circuit, only resistor is present, then the current and voltage in the circuit work in the same phase.

Hence, Phase difference between V and I is 0.

Step 4

We know,

Impedance in a circuit is given by Z , here, in the circuit, Inductor and capacitor is not present hence, the impedance in the circuit will be solely the resistance in the circuit.

Z=R

Using Ohm's law, I=\frac{V}{Z}

Hence, Z=\frac{V}{I}    or  R=\frac{V}{I}

Substituting the given values, we get

R=\frac{200}{5}  ; or

R=40Ω

Hence, the impedance of the circuit is 40Ω.

Final answer:

Hence,

  1. Peak value of current is 5A and peak value of EMF is 200V.
  2. Frequency of the AC source is 50 Hz.
  3. Phase difference between V and I is 0^{o}.
  4. Impedance of the circuit is 40Ω.
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