Question

19. In dividing a certain number by 2, 3 and 7 in
succession, the remainders are 1, 1 and 6
respectively and the last quotient is 169. Find
the number.​

Answer 1

Answer:

Step-by-step explanation:

We take from back

least quotient q=169, d=7 and r=6 we can write as

dividend=169*7+6=1189

Previous d= 3 and r=1

then dividend=1189*3+1=3568

Previous d= 2 and r=1

so Number=3568*2+1=7137