Question

19. In fig. OA = OB and OD = 0C. Show that A AOD SA BOC
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Answer 1

$\underline{\underline{\maltese\: \: \textbf{\textsf{Correct Question: - }}}}$

In the figure OA = OB and OD = OC Show that

(a) △AOD ≅△BOC

(b) AD || BC

$\underline{\underline{\maltese\: \: \textbf{\textsf{Answer : - }}}}$

In△AOD&△BCO

$\sf \longrightarrow \: OD=OC \: (given) \\ \\ \sf \: OA=OB \: (given) \\ \\ \sf \: ∠AOD=∠COB (vertically opposite) \\ \\ \sf \longrightarrow \red{△AOD≅△BOC}$

∠OAD=∠OBC -----------------(angles corresponding to congruent sides)

[∵ AD & BC make equal angles with the same line AB]

$\sf \therefore \: Hence \: \red{AD∣∣BC}$