Question

19) In the figure AP=PQ ,BQ=QC .Area of triangle ABC is 100 sq.cm then find area of triangle BPC *​

Answer 1

Answer:

50

Step-by-step explanation:

area of triangle

$1 \div 2b \times h$

then ∆ABC triangle height is double of that of ∆BPC

then area will be half of ∆ABC