19. In the figure, APAB is formed by three tangents to a circle with centre O. If APB = 40", find AOB.
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→ Angle APB = 40°
→ PT and PR are tangents and tangents are perpendicular to center
So,
→ Angle PAO = 90°
→ Angle PBO = 90°
Sum of angles of quadrilateral PAOB → 360°
→ Angle APB + Angle PAO + Angle PBO + Angle AOB = 360°
→ 40° + 90° + 90° + Angle AOB = 360°
→ Angle AOB = 360° - 220
→ Angle AOB = 140°
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