Math, asked by krishnabgp73, 1 month ago

19. In the given figure, BI is the bisector ofABC and CI is the bisector of ACB, Find BIC.
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Answers

Answered by Allien52
1

Answer:

please insert your figure dear it is not sufficient to gave solution

Answered by saniadcunha10
1

Step-by-step explanation:

In ∆ ABC,

BI is the bisector of ∠ABC and CI is the bisector of ∠ACB.

∵ AB = AC

∴ ∠B = ∠C

(Angles opposite to equal sides)

But ∠A = 40°

and ∠A + ∠B + ∠C = 180°

(Angles of a triangle)

⇒ 40° + ∠B + ∠B = 180°

⇒ 40° + 2∠B = 180°

⇒ 2∠B = 180° - 40° = 140°

⇒ ∠B = 140°/2 = 70°

∴ ∠ABC = ∠ACB = 70°

But BI and Cl are the bisectors of ∠ABC and ∠ACB respectively.

∠IBC = 1/2 ∠ABC = 1/2 (70°) = 3

and ∠ICB = 1/2 ∠ACB = 1/2 × 70°= 35

Now in ∆ IBC,

⇒ ∠BIC + ∠IBC + ∠ICB = 180°

(Angles of a triangle)

⇒ ∠BIC + 35° + 35° = 180°

⇒ ∠BIC = 180° - 70° = 110°

Hence ∠BIC = 110°

Hope it helps you

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