19. In triangle ABC, AB = AC = 15 cm and BC = 18 cm. Find : (i) cos B (ii) sin C (iii) tan? B - sec2 B + 2
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In triangle ABC, AB=AC=15 cm and BC=18 cm. Find:
tan
2
B−sec
2
B+2
Medium
Solution
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Correct option is A)
AB=AC=15, BC=18
Using cosine rule,
AC
2
=BC
2
+AB
2
−2(AB)(BC)cosB
15
2
=18
2
+15
2
−2(15)(18)cosB
cosB=
15
9
cosB=
5
3
cosB=
H
B
=
5
3
Now, using Pythagoras theorem.
H
2
=P
2
+B
2
5
2
=P
2
+3
2
P=4
tan
2
B−sec
2
B+2
= (
B
P
)
2
−(
B
H
)
2
+2
= (
3
4
)
2
−(
3
5
)
2
+2
=
9
16−25+18
= 1
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