Question

19. In triangle AOB and COD, angle B = angle C and O is the
midpoint of BC. Find the values of x and y if AB = 3x units, CD = y + 2 units, AO = x + 2 units, DO = y units.
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Answer 1

Step-by-step explanation:

Given

∆AOB and ∆COD

angle B=angle C

O is the midpoint of BC

AB=3x

CD=y+2

AO=x+2

DO=y

Proof: angle B=angle C

So AB||CD and BC is transversal (Any two line bisect other transversal line and whose opposite angle are equal ,so two lines are equal)

Answer 2

Answer:

x=2, y=4

I hope this helps. Thanks!