Question

19.
In triangles ABC, if angleA-AngleB=33º and angleB -angleC=18°then measure of B
is
A
(b) 550
(a) 880
(d) 370
(c) 600​

Answer 1

Answer:

hence ...in a triangle ...

angle A + angle B + angle C = 180° .... (i)

a/c to question,

angle A - angle B= 33°

So..angle A = 33 + angle B. ....(ii)

and..

angle B - angle C = 18°

so, angle C = angle B - 18° ...... (iii)

putting (ii) and (iii) in (i)

So...

angle A + angle B + angle C = 180°

so...

33° + angle B + angle B + angle B - 18° = 180 °

so, 3× angle B + 15 = 180°

so...angle B = (180 - 15 )/3

= 165/3

= 55°

so...angle B is 55°

so...b is correct