Question

19. IUPAC name of K, [OsCI N] will be
(1) Potassium pentachloroazido osmate (VIII)
(2) Potassium pentachloroazido osmate (VI)
(3) Potassium pentachloro nitrido osmate (VI)
(4) Potassium nitro osmate (III)​

Answer 1

Answer:

4 Potassium nitro osmate [III]

Explanation:

oxidation no of K is +1 so total charge on complex will be -1

as it is initially neutral

oxidation no of chloride is -1 and of azide is -3

let oxidation no of Os be x

so

x+[-1]+[-3]= -1

x-4=-1

x=+3

so oxidation no of Os is 3 so 4 will be ans

hope it helps

plz mark brainliest