Question

19. PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.​

Answer 1

Hey mate! Here is your answer:

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)  

2

=(Base)  

2

+(Perpendicular)  

2

 [By Pythagoras theorem]

⇒(QR)  

2

=(PQ)  

2

+(PR)  

2

 

⇒x  

2

=(10)  

2

+(24)  

2

 

⇒x  

2

=100+576=676

⇒x=  

676

​  

=26cm

Thus, the length of QR is 26cm.

Hope it helps you ✌

Answer 2

Answer:

Refer to the attachment above. ⬆️

hope it helps!!