19
R-30
R-050
SECTION
a) Five resistors are connected in a circuit as shown. Find the ammeter reading when circuit is
closed
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Answer:Labelling each of the resistance as shown in the figure below.
Resistance R
1
and R
2
are in series
⇒ R
s1
=R
1
+R
2
⇒ R
s1
=3+3=6 Ω
Now R
s1
and R
3
are in parallel.
⇒
R
p
1
=
R
s1
1
+
R
3
1
⇒
R
p
1
=
6
1
+
3
1
⇒
R
p
1
=
6
1+2
=
6
3
⇒R
p
=
3
6
=2
⇒R
p
=2 Ω
Now R
4
,R
p
and R
5
are in series.
⇒R
eq
=R
4
+R
5
+R
p
⇒R
eq
=0.5+2+0.5=3 Ω
Hence the Equivalent resistance of the circuit is 3 Ω.
For Ammeter Reading
Current (I)=
R
V
=
3
3
=1A
Hence the current reading in ammeter is 1 A.
Explanation:
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