Question

19. Solve : 3x+2y=13 and x+3y=9
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Answer 1

Answer:

x = 3 , y = 2

Step-by-step explanation:

3x + 2y=13  ========> [1]

x+ 3y = 9    =========> [2]

Multiply [2] by 3 and subtract from [1]

3x + 9y = 27

3x + 2y = 13

-    -         -

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7y = 14

=> y = 2

Substitute the value of y in [2]

x + 3y = 9

=> x + 6 = 9

=> x = 3.

Answer 2

Answer:

Step-by-step explanation:from equation 1

X=13-2y/3 ......(3.)

Putting value of x in eq 2.

= 13-2y/3+3y=9

Take L.C.M.

= 13-2y+9y/3=9

= 13-2y+9y=27

= 16+7y=27

= 7y= 27 -16

= 7y=11

= y=11/7

Putting value of y in eq 3.

= x=13-2×11/7÷3

= x=13-22/7×3

= x=13-22/21

= x=9/21

= x=3/7

ans. The value of 'X' and 'Y' is 11/7

And 3/7