19. The driver of a car traveling along a straight road with a speed of 72KM ph observes a signboard which give the speed limit to be 54KM ph. The signboard is 70m ahead when the driver applies the brakes0 calculate the acceleration of the car which will cause the car to pass the signboard at the stated speed limit?
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heya...
u = 72 km/h = 20 m/sv
= 54 km/h = 15 m/sS
= 70 ma = ?
v² = u² - 2×a×S (because there will be deceleration)
15² = 20² - 2×a×70225
= 400 - 140 a140
a = 400-225140
a = 175a
= 175/140a
= 1.25 m/s²Acceleration will be -1.25 m/s².
tysm...#gozmit
u = 72 km/h = 20 m/sv
= 54 km/h = 15 m/sS
= 70 ma = ?
v² = u² - 2×a×S (because there will be deceleration)
15² = 20² - 2×a×70225
= 400 - 140 a140
a = 400-225140
a = 175a
= 175/140a
= 1.25 m/s²Acceleration will be -1.25 m/s².
tysm...#gozmit
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