Question

19. The equation to two circles which touch the Y-axis at (0, 3) and make an intercept of 8 units
X-axis are
1) x2 + y2 + 6x-10y +9 = 0
2) x2 + y2 #10x - 6y+9 = 0)
3) x2 + y2 +10x + 6y+9=0
x2 + y2 - 8x +10y +9 = 0​

Answer 1

Answer:

Answer is

${x}^{2} + {y}^{2} + 10x - 6y + 9 = 0$

Explanation:

Just put x = 0 and y = 3 in all equations and see where LHS = RHS.

The above equation qualifies. :)