Question

19. The figure shows a trapezium ABCD with
two circles of equal diameter drawn in it.
If ON=56 cm and PM IBC; PM = 42 cm,
AD = 30 cm and BC = 64 cm, find the area
of the shaded region.​

Answer 1

Answer:

742

Step-by-step explanation:

area of both circles are equal as the radius is the same;

diameter of circle =0N /2;

                              = 28;

therefore radius = 14cm

area of both circles =2(1/2pie radius square);

=2(22/7 *14*14)

= 1232;

area of trapezium = 1/2h(sum of parallel sides);

=1/2*42(30+60);

=1974

area of shade region=area of trapezium-are of both circles;

=1974-1232;

=742 cm square