Question

19. The following table gives the literacy rate of 40 cities:Literacy 30-40 40-50 50-60 60-70 70-80 80-90rate (in %)Number ofcities6 7 10 6 8 3​

Answer 1

Answer:

54.28

Step-by-step explanation:

l = 50, h = 10, f1 = 10, f0 = 7, f2 = 6

Mode = l+h((f1-f0)/2f1-f0-f2)

          = 50 + 10 ((10-7)/20-7-6)

          = 50 + 10 (3/7)

          = 50 + 30/7

          = 350/7 + 30/7

          = 380/7

          = 54.28

Answer 2

Step-by-step explanation:

Given The following table gives the literacy rate of 40 cities: Literacy 30-40 40-50 50-60 60-70 70-80 80-90 rate (in %)Number of cities          6 7 10 6 8 3

• So we need to find the mode of the following table
• Literacy rate(%) 30-40  40-50  50-60  60-70  70-80  80-90  
• Number of cities            6            7           10           6             8           3
• So from the table we have maximum class frequency is 10 and the class interval is 50-60
• So the modal class is 50-60
• Now lower class limit of modal class l = 50
• Frequency of modal class is f1 = 10
• Frequency preceding the modal class fo = 7
• Frequency succeeding the modal class f2 = 6
• Size of class h = 10
•               Now Mode = l + (f1 – fo / 2f1 – fo – f2) x h
•                                   = 50 + (10 – 7 / 2(10 – 7 – 6)
•                                  = 50 + 3/7 x 10
•                                  = 50 + 30 / 7
•                                    = 350 + 30 / 7
•                                    = 380 / 7
•                                    = 54.28              

Reference link will be

https://brainly.in/question/39793713