Question

19)))). The graph between capacitance of a parallel plate capacitor and charge on a capacitor is( charge is within breakdown limit of capacitor)

a) straight line inclined to charge axis
b) straight line parallel to charge axis
c) straight line parallel to capacitance axis
d) parabola

Answer 1

Answer:

Explanation:

(i) The capacitance increases as the dielectric constant K>1.  

(ii) Potential difference V=  

C

Q

​

.  As C increases and Q remains the same since the battery is disconnected, the p.d. between the plates decreases.

(iii) Electric field E=  

d

V

​

 where V is the p.d. and d the separation between the plates. As V decreases and d remains the same, electric field also decreases.

(iv) Energy stored in a capacitor U=  

2

1

​

 

C

Q  

2

 

​

. As Q is constant and C increases, U decreases.

Answer 2

Answer:

The capacitor is independent of the charge. Hence, the correct option is (b) a straight line parallel to the charge axis,

Explanation:

Capacitance is defined as the ratio of the amount of electric charge stored on a conductor to the difference in electric potential, when the values are substituted the capacitance becomes directly proportional to the area and inversely proportional to the distance and independent of charges.

As the capacitance is independent of charges, it is constant with respect to charges.

Hence, the graph between the capacitance of a parallel plate capacitor and the charge on a capacitor is a straight line parallel to the charge axis.

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