19. The median of five consecutive integers is N. (a) Find the mean of the five numbers. (b) Find the mean and the median of the squares of the integers. (c) Find the difference between these values.
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SOLUTION If the average (arithmetic mean) of 5 consecutive numbers is 13, what is the average of the first 4 of these integers?
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7 Answers
Asked in 1 Space

Mohd Iqmal Mamat
, someone between an engineer and a mathematician
Answered Jan 22, 2018
Originally Answered: If the Average (arthematite mean) of 5 consecutive numbers is 13, What is the Average of the first 4 of these integers?
Let the 5 consecutive numbers be denoted as x,x+1,x+2,x+3,x,x+1,x+2,x+3,and x+4x+4, respectively.
It is given that their average is 1313.
Therefore,
(x+(x+1)+(x+2)+(x+3)+(x+4))/5=13(x+(x+1)+(x+2)+(x+3)+(x+4))/5=13
Simplifying the fraction gives
(5x+10)/5=13(5x+10)/5=13
5x+10=655x+10=65
5x+10−10=65−105x+10−10=65−10
5x=555x=55
x=55/5x=55/5
x=11x=11
Therefore, the five consecutive numbers are 11,12,13,1411,12,13,14and 1515.
Now, to answer the question, the average of the first four consecutive numbers is
(11+12+13+14)/4=12.5(11+12+13+14)/4=12.5
The answer is 12.5