Question

19. The near point of a hypermetropic eye is at 75 cm from the eye. What is the power of the
lens required to enable him to read clearly a book held at 25 cm from the eye?​
please answer me

Answer 1

i hope this will help you

Answer 2

Heyaa ... ^_^

here is your answer...

-> v=-75cm

= u=25cm

=1/v + 1/u = 1/f

=1/-75 + 1/25 = 2/75

= P = 1/f

= 100/(75/2)

= 2.66D

>>2.66D is the answer<<

hope it may help you...^_^