Question

19
the perimeter of a triangle is 72 cm and its side are in the ratio of 1 :2:3 find its sides.
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Answer 1

☑️ Correct Question:

• the perimeter of a triangle is 72 cm and its side are in the ratio of 1 :2:3 find its sides.

☑️Given:

• perimeter of a triangle is 72 cm
• side are in the ratio of 1 :2:3

☑️To find:

• Sides of triangle

☑️ Assumption:

• Let the sides of triangle be y;

☑️ Solution:

• First side is y
• second side is 2y
• third side is 3y

it is given that sum of sides of triangle = 72cm

therefore,

= y+2y+3y= 72

= 6y = 72

= y = 72/6

= y = 12

Hence,

☑️first side is y = 12 cm

☑️second side is 2y = 2 x 12 = 24cm

☑️third side is 3y = 3 x 12 = 36cm

Final answer :-

12cm , 24cm , 36cm

Answer 2

${ \large{ \implies{ \sf{Let \: \: the \: \: first \: \: side \: \: be \: \: 1x}}}}$

${ \large{ \implies{ \sf{Second \: \: part = 2x}}}}$

${ \large{ \implies{ \sf{Third \: \: side = 3x}}}}$

${ \large{\pink{ \star \: \: \:{ \rm{Perimeter \: \: of \: \: triangle }}}}} = \: { \large{\pink{ \boxed{ \rm{side + side + side}}}}} ={ \large{\pink {\rm{ 72 \: cm}}}} \:{ \bf (given)}$

${ \large{ \implies{ \sf{x + 2x + 3x = 72}}}}$

${ \large{ \implies{ \sf{6x = 72}}}}$

${ \large{ \implies{ \sf{x = \dfrac{ \cancel{72} \: {}^{12} }{ \cancel{6} }}}}}$

${ \large{ \therefore{ \bf{First \: \: side = x = 12 \: cm}}}}$

${ \large{ \therefore{ \bf{Second \: \: side = 2x = 24 \: cm}}}}$

${ \large{ \therefore{ \bf{Third \: \: side = 3x = 36 \: cm}}}}$