Question

19. The perimeter of a triangle is (7x2 - 8y +9) and two of its sides are (9x2 - y + 1) and (4x2 - 3y + 5), find the
third side
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Answer 1

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Step-by-step explanation:

let us take the third side as x

(7×2-8y+9) = (23-8y)

(9×2-y+1) = (15-y)

(4×2-3y+5) = (13-3y)

So, (15-y) + (13-y) + x = (23-8y)

or 15-y+13-y+x = 23-8y

or 28-2y+x = 23-8y

or x = -28+23+2y-8y

or x = -5 - 6y