Question

19. The sides of triangle are 4x + 3y ,7x-2y
and 14x - 5y. Find its perimeter.
*​

Answer 1

Answer:

A= 4x+3y

B= 7x-2y

C= 14x-5y

Perimeter of triangle = Sum of all three sides

$perimeter = 4x + 3y + 7x - 2y + 14x - 5y$

$= 4x + 7x + 14x + 3y - 2y - 5y$

$= 25x + 3y - 7y$

$= 25x - 4y$

Answer : perimeter of triangle = 25x - 4y

Answer 2

Answer:

Perimeter= 25x-4y

Step-by-step explanation:

Given :

The sides of triangle are 4x + 3y ,7x-2y

The sides of triangle are 4x + 3y ,7x-2yand 14x - 5y.

To find :

Perimeter of the triangle

Solution:

Given sides are :

Let a = 4x + 3y

b= 7x-2y

c = 14x - 5y

Perimeter= Sum of all sides

Perimeter= a+b+c

Perimeter= (4x + 3y)+(7x-2y)+ (14x - 5y)

Perimeter = (4x+7x+14x)+(3y-2y-5y)

Perimeter = ( 25x) + ( -4y)

Perimeter= 25x-4y

Points to remember:

• The sum of all the sides of c a closed figure is the perimeter of the given figure.