19. The two adjacent sides of a rectangle are 5x2 - 3y2 and x2 + 2xy find the perimeter.
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Answer:
12x² - 6y² - 4xy
Step-by-step explanation:
Perimeter of a rectangle = 2(l+b)
Let's take
l = 5x² - 3y²
And,
b = x² + 2xy
Solving
2((5x² - 3y²) + (x² + 2xy))
= [(2 × 5x²) - (2 × 3y²)] + [(2 × x²) + (2 ×2xy)] (Distributive property)
= 10x² - 6y² + 2x² + 4xy
= 10x² + 2x² - 6y² + 4xy(here 10x² and 2x² are like terms... so we add them)
= 12x² - 6y² + 4xy
Therefore, the perimeter of the rectangle is 12x² - 6y² + 4xy
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