19.The value of (√80-√112)/(√45-√63)
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Answered by
30
Given (root 80 - root 112)/(root 45 - root 63)
= - (root 112 - root 80)/- (root 63 - root 45)
= (root 112 - root 80)/(root 63 - root 45)
= 4 root 7 - 4 root 5/ 3 root 7 - 3 root 5
= 4(root 7 - root 5)/(3(root 7 - root 5)
= 4/3.
Hope this helps!
= - (root 112 - root 80)/- (root 63 - root 45)
= (root 112 - root 80)/(root 63 - root 45)
= 4 root 7 - 4 root 5/ 3 root 7 - 3 root 5
= 4(root 7 - root 5)/(3(root 7 - root 5)
= 4/3.
Hope this helps!
Answered by
6
Answer:
Given (root 80 - root 112)/(root 45 - root 63)
= - (root 112 - root 80)/- (root 63 - root 45)
= (root 112 - root 80)/(root 63 - root 45)
= 4 root 7 - 4 root 5/ 3 root 7 - 3 root 5
= 4(root 7 - root 5)/(3(root 7 - root 5)
= 4/3.
Step-by-step explanation:
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