Question

19. The value of a house increases by 10% every year. Its
present value is 38,80,000.
(i) What will be its value 2 years later?
(ii) What was its value 1 year ago?​

Answer 1

Answer:-

$\small \bf \underline{Given:}$

★★ Present value of the house = ₹ 38,80,000

★★ The value of the house increases 10% per year

$\small \bf \underline{To \: find:}$

We need to find

(i) The value of the house 2 years later

(ii) Value of the house 1 year ago

$\small \bf \underline{Solution:}$

(i) After 1 year ,

Increase = 10% of present value

$\small \bf = \frac{10}{100} \times 38,80,000$

$\small \bf = ₹ \: 3,88,000$

So value of the house after 1 year = ₹ ( 38,80,000 + 38800 )

= ₹ 42,68,000

After 2 years,

Increase = 10% of ₹ 426,800

$\small \bf = \frac{10}{100} \times 42,68,000$

$\small \bf = 4,26,800$

Value after two years = ₹ (42,68,000 + 4,26,800)

= ₹ 4,694,800

(ii) Let the value of one year earlier be x

Then, according to the question

$\small \bf \: x + \frac{x}{10} = 38,80,000$

$\small \bf \implies \: 11x = 3,88,00,000$

$\small \bf \implies \: x = \frac{3,88,00,000}{11}$

$\small \bf \implies \: x = 3,527,272.73$

Answer: (i) The value of the house 2 years later = ₹ 4,694,800

(ii) Value of the house 1 year ago = ₹ 3,527,272.73

@BengaliBeauty

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