Question

19. The value of b2 - 4ac in the equation V2 x2-5x +V2 = 0 is​

Answer 1

Answer:

simple

Step-by-step explanation:

Answer 2

$\sf\huge\bold{Answer:}$

= 17

Given :

Quadratic equation : √2x²-5x+√2=0

To find :

• Discriminant(b²-4ac)

Solution :

• General form of quadratic equation :

→ax²+bx+c=0

• Given equation :

→√2x²-5x+√2=0

• On Comparing, we get

a=√2

b= -5

c= √2

• Discriminant

→D=b²-4ac

→D=(-5)²-4(√2)(√2)

→D=25-4(√2×√2)

→D=25-4×2

→D=25-8

→D=17

Hence, b²-4ac for √2x²-5x+√2=0 is 17