19) The vapour density of a volatile chloride of divalent metal is 59.5 and equivalent mass of the metal is... 1) 96 2)48 3)24 4)12
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Vapour Density of chloride of a metal =59.5
Equivalent Mass of a metal =24
According to formula,
Molar mass of chloride=2×VapourDensity
=2×59.5
=119
Equivalent Mass=
n−factor
Molar Mass
⇒24=
n
x
35.5n+x=2×59.5
35.5n+24n=119
⇒x=2
Molar mass of element =48g/mol
HOPE IT HELPS YOU!!!
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Answer:
Explanation:
molecular mass of metal chloride = 119
molecular mass of divalent metal chloride is 2w+71 = 119
w=24
proof
equivalent mass of divalent metal atom is w suppose
then mass of divalent metal = 2w
mass of chloride = 71 bcoz formula is mcl2
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