Question

19. Two candidates A and B contested an election. The total votes polled were 9650. If A got 54% of
the votes, find the number of votes received by each.
​

Answer 1

Answer:

A = 5211 votes. B = 4439 votes

Step-by-step explanation:

total votes polled = 9650

Percentage of votes A got = 54%

No of votes received by A = 54% of 9650

= (54/100)× 9650

= 5211

No of votes received by B = 9650 - 5211

= 4439

Answer 2

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total votes = 9650

votes of A = 54% of 9650

let candidate A received V1 votes,

$\implies \: votes \: of \: a \: =9650 \times \frac{54}{100} \\ \implies \:v1 = 965 \times \frac{54}{10} \\ \implies \: v1= 965 \times \frac{27}{5} \\ \implies \: v1 = 193 \times 27 \\ \implies \: v1 = 5211$

so candidate A received 5211 votes.

now, let candidate B received V2 votes,

$\implies \: v2 = 9650 - v1 \\ \implies \: v2 = 9650 - 5211 \\ \implies \: v2 = 4439$

so candidate B received 4439 votes.

hence,

candidate A received 5211 votes and Candidate B received 4439 votes