Question

19. Two persons A and B start walking in opposite
directions at 8 a.m. from two places which are
27 km. apart. Both of them meet at 11 a.m. If
A's speed is 3 km/hr more than that of B, find
their respective speeds.
A. 4 km/hr, 8 km/hr B. 3 km/hr, 6 km/hr
C. 1 km/hr, 2 km/hr D. 5 km/hr, 10 km/hr​

Answer 1

Step-by-step explanation:

answer answer is b

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Answer 2

We need to recall that

$Distance=speed\[\times \]time$

Now, let's solve the problem.

Given: A and B are $27km$ apart.

Step 1 of 2: Let $xkm/h$ be the speed of B

Then speed of A will be$(x+3)km/h$

And let the distance covered by B be $ykm$. Therefore, the distance covered by A will be $(27-y)km$.

Step 2 of 2:

We know that $Distance=speed\[\times \]time$

Therefore,

$27-y=(x+3)3\\3x+y=18..............(1)$

And, distance covered by B

$y=3x$

Put this in equation $(1)$

We get,

$x=3$

Final answer:

Speed of A is $6km/h$

Speed of B is$3km/h$

Therefore, the correct option is B.