Question

19. Two semicircular flower beds are made on the
outside of the smaller sides of a rectangular
garden 16 m by 7 m. Find the total area and
perimeter

The answer is 150.5m2 , 54m

No spam if u will keep uncessary answers I will report all ur answers and delete them


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Answer 1

Given :

• Sides of rectangle are, 16m & 7m
• Diameter of semi-circle = 7m

To find :

• Area of Given figure
• Perimeter of given figure

Formula used :

• Area of rectangle = length× Breadth
• Area of semi-circle = πr²/2
• Perimeter of semi-circle = πr + d

Solution :

◈ Area of given figure = Area of semi-circle{1} + Area of rectangle + Area of semi-circle{2}

$\sf \implies \: Area \: of \: given \: figure \: = \: \dfrac{\pi {( 3.5)}^{2}}{2} + (16 \times 7) + \dfrac{\pi {( 3.5)}^{2}}{2} \\ \\ \sf \implies \: Area \: of \: given \: figure \: = \dfrac{22}{7} \times \dfrac{12.25}{2} + (112) + \dfrac{22}{7} \times \dfrac{12.25}{2} \\ \\ \sf \implies \: Area \: of \: given \: figure \: = \: 19.25 + 112 + 19.25 \\ \\ \sf \implies \: Area \: of \: given \: figure \: =150.5 {m}^{2}$

◈ Perimeter of given figure = (Perimeter of semi-circle{1} - diameter) + (2× long side of rectangle) + (Perimeter of semi-circle{2} - diameter)

➩ Perimeter of given figure = { ( πr + d) - d } + (2×16) + { (πr +d )- d }

➩ Perimeter of given figure = πr + (32) + πr

$\sf \implies \: Perimeter \: of \: \: given \: figure \: = \: \dfrac{22}{7} \times 3.5 \: + \: 32 \: \dfrac{22}{7} \times 3.5 \\ \\ \sf \implies \: Perimeter \: of \: \: given \: figure \: =11 + 32 + 11 \\ \\ \sf \implies \: Perimeter \: of \: \: given \: figure \: = \: 54 \: m$

ANSWER :

• Area = 150.5 m²
• Perimeter = 54 m

Answer 2

Answer:

hi lucky

Step-by-step explanation:

but you know if my answers and questions got deleted in a row with a huge amount ..I am sure I am leaving this app

you know 2 days ago my 82 answers in row got deleted....

and here is your answer..in the attachment..

sorry took from web