Question

19. Two tetrahedral dice and a fair 6- faces die are rolled simultaneously. The number on the tetrahedral dice are 1, 2, 3 and 4;while the number on the 6 - faces die are 1, 2, 3, 4, 5 and 6.On the basis of the above information, answer the following questions :(i) What is the probability that the scores on 6-faces die is greater than the sum of scores of the two tetrahedral dice?​

Answer 1

Answer:

tetrahedral dies numbering are 1,2,3,4

and six sided dies numbering are 1,2,3,4,5,6

after throwing simultaneously, total possible outcomes = 6*4*4=96

Given condition is, six die number should be greater than sum of two tetrahedral dies

all cases are given as,

for six sided die>(tetrahedral die)

3>(1+1)= 1 case

4>(1+1,1+2,2+1)= 3 cases

5>(1+1,1+2,2+1,3+1,1+3,2+2)= 6 cases

6>((1+1,1+2,2+1,3+1,1+3,2+2,4+1,1+4,3+2,2+3)= 10 cases

total cases are=1+3+6+10=20

probability of given Question=total cases/total possibility

=20/96=5/24