Question

19
What sum will amount to 6600 in 4
yrs
at
8% per annum simple interest? [JNV 2019)
(1) *6000 (2) 5000
(3) 4000 (4) 6200​

Answer 1

${ \huge {\bold{Answer:}}}$

Formula used࿐

• Principal= (Interest×100)/(Time×Rate)
• Interest= (p×r×t)/100
• Amount= Principal+Interest

Solution࿐

Given,

Amount=Rs.6600

Time= 4year

Rate= 8%

Now,

$\bold{S.I= \frac{p \times r \times t}{100} }$

$= > \bold{S.I = \frac{p \times 8 \times \cancel{ 4}}{ \cancel{100} \: \: ^{25} } }$

$= > \bold{S.I = \frac{8p}{25} }$

Therefore, The simple Interest is 8p/25.

Let the Principal be"p"

$\bold{6600 = \frac{8p}{25} + p}$

$= > \bold{ \frac{8p + 25p}{25} = 6600 }$

$= > \bold{33p = 6600 \times 25}$

$= > \bold{p = \frac{6600 \times 25}{33} }$

$= > \bold{p = 200 \times 25}$

$= > \bold{p = 5000}$

Therefore, The Principal is RS.5000 .